Question

What is the equation of a line, in slope-

intercept form, perpendicular to 4x-2y = 8
and passing through point (6, 4)?

Answer 1

Answer:
y = 2x - 4 slope: 2 y intercept: -4
equation of perpendicular line pass (1,2): y = -1/2 * x + 2.5
Explanation:
4x - 2y = 8
2y = 4x - 8
y = 2x - 4
slope: 2
y intercept: -4
slope of perpendicular line: -1/2
2 = -1/2 * 1 + b
b = 2.5
equation of perpendicular line pass (1,2): y = -1/2 * x + 2.5