Answer: 120 ways
Explanation:
Let's label the routes a, b, c, d, and e. The goal is to come up with as many unique permutations as possible.
1 route: a=1. one factorial (1!) =1*1=1
2 routes: ab, ba=2. 2!=1*2=2
3 routes: abc, acb, bac, bca, cab, cba=6. 3!=1*2*3=6
4 routes: 4!=1*2*3*4=24
5 routes: 5!=1*2*3*4*5=120 ways