Question

I need to perform the operation

Answer 1

`( - 5x^(2) * - 4x \: - 1)( - 4^(2) - 4x)`

`(((0 - (5 • ( { * }^(2) ))) - 4x) - 1) + ((0 - {2}^(2) {x}^(2) ) - 4x)`

`(((0 - 5 {x}^(2) ) - 4x) - 1) + ( - 4 {x}^(2) - 4x)`

Full out like factors:

`- 9 {x}^(2) - 8x - 1 • = - 1(9 {x}^(2) + 8x + 1`

Factoring

`9 {x}^(2) + 8x + 1`

The first term is,
`9 {x}^(2)` its coefficient is 9 .

The middle term is,
`+ 8x` its coefficient is 8 .

The last term, "the constant", is
`+ 1`

Step-1 : Multiply the coefficient of the first term by the constant 9 • 1 = 9

Step-2 : Find two factors of 9 whose sum equals the coefficient of the middle term, which is 8 .

`-9x^2 - 8x - 1`

Answer 2

(-5
`x^(2)` -4x-1)+(-4
`x^(2)`-4x)

=-5
`x^(2)` -4x-1-4
`x^(2)`-4x

=-9
`x^(2)`-8x-1