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Find the formulae for the m" term of 7 ;13 ;19 ;25 ;31​

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Answer:


a_(n) = 6n + 1

Explanation:

there is a common difference between consecutive terms , that is

13 - 7 = 19 - 13 = 25 - 19 = 31 - 25 = 6

this indicates the sequence is arithmetic with n th term


a_(n) = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

here a₁ = 7 and d = 6 , then


a_(n) = 7 + 6(n - 1) = 7 + 6n - 6 = 6n + 1

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