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Solve the equation on the interval [0,2π). 2 sin x -1=0
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5 votes
Solve the equation on the
interval [0,2π).
2 sin x -1=0

Solve the equation on the interval [0,2π). 2 sin x -1=0-example-1
User Rogersillito
by
7.6k points

1 Answer

4 votes

Answer: pi/6, 5pi/6

Explanation:

2sinx-1=0

2sinx=1

sinx=1/2

sin is positive in y axis so it is pi/6, 5pi/6

User Ahmad Mayo
by
6.7k points
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