Hi
A standard quadric equation is : ax² +bx +c = 0
discriminant is : b² -4*a*c
3 cases can occur :
Discriminant is strictly positive , then equation has two Real solutions.
If discriminant is equal at 0 , there is one solution ( to be honest, there is 2 identical solutions )
If discriminant is negative, so there is 2 imaginary / complex solutions.
So :
-7x² -5x +5 = 0
here : a = -7 ; b = -5 and c = 5
So discriminant : dis = (-5)²- 4 *(-7) * ( 5)
= 25 - 4*-35
= 25 + 140
= 165
165 is strictly superior to 0, so the equation has two real solutions.