Question

A motorcycle has a constant acceleration of 2.5 meters per second squared

Both the velocity and acceleration of the motorcycle point in the same direction

How much time is required for the motorcycle to change its speed from 21 to 31 m/s z

Answer 1

`given \\ accelaration (a)= 2.5 \frac{m}{ {s}^(2) } \\ initial \: velocity(u) = 21 (m)/(s) \\ final \: velocity(v) = 31 (m)/(s) \\ we \: want \: find \: time \\ newtons \: equation \: of \: motion \: v = u + at \\ 31 = 21 + 2.5 * t \\ 31 - 21 = 2.5t \\ 10 = 2.5t \\ (10)/(2.5) = t \\ t = 4sec`