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A plane traveled 1071 miles each way to Casablanca and back. The trip there was with the wind.
It took 7 hours. The trip back was into the wind. The trip back took 9 hours. Find the speed of
the plane in still air and the speed of the wind.

User Jo Momma
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1 Answer

3 votes

Answer:

  • plane: 136 mph
  • wind: 17 mph

Explanation:

The relation between time, speed, and distance can be used to write equations for the speeds in each direction.

Setup

Let p and w represent the speeds of the plane and the wind, respectively. The speed with the wind is ...

speed = distance/time

p +w = 1071/7 = 153

The speed against the wind is ...

p -w = 1071/9 = 119

Solution

The plane's speed can be found by adding these two equations:

(p +w) +(p -w) + (153) +(119)

2p = 272

p = 136 . . . . . divide by 2

The wind speed can be found from either equation:

w = p -119 = 136 -119 = 17

The speed of the plane in still air is 136 miles per hour; the speed of the wind is 17 miles per hour.

User Metric Scantlings
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