Question

Find the zero of the polynomial in each of the following cases

(I) P(x) = 3x - 2
(II) P(x) = 9x
(III) P(x) = cx + d, c ≠ 0, c and d are real numbers​

Answer 1

(I) 2/3 is a zero of P(x)

(II) 0 is a zero of P(x)

(III) (-d/c) is a zero of P(x)

Explanation:

(I) P(x) = 3x - 2

Here, P(x) = 3x - 2

To find the zeroes of P(x)

let P(x) = 0

∴ 3x - 2 = 0

∴ 3x = 2

∴ x = 2/3

Thus, 2/3 is a zero of P(x)

(II) P(x) = 9x

Here, P(x) = 9x

To find the zeroes of P(x)

let P(x) = 0

∴ 9x = 0

∴ x = 0/9

∴ x = 0

Thus, 0 is a zero of P(x)

(III) P(x) = cx + d, c ≠ 0

Here, P(x) = cx + d

To find the zeroes of P(x)

let P(x) = 0

∴ cx + d = 0

∴ cx = -d

∴ x = (-d/c)

Thus, (-d/c) is a zero of P(x)

-TheUnknownScientist