Question

point p to Point q is 15 km away and on a bearing of 090°to a point R is 8 km from q. find the distance between p and r​

Answer 1

Check the picture below.

`\textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=√(a^2 + b^2) \qquad \begin{cases} c=\stackrel{hypotenuse}{RP}\\ a=\stackrel{adjacent}{15}\\ b=\stackrel{opposite}{8}\\ \end{cases} \\\\\\ RP=√(15^2+8^2)\implies RP=√(225+64)\implies RP=17`