Question

Find a2 and a3 for the following geometric sequence:

4, a2, a3, 108

Answer 1

12 and 48

Explanation:

Let a be the first term and r be the common ratio.

We know that a = 4, and that ar³ = 4r³ = 108, and thus r = 3.

Therefore

`a_2=12, a_3=48`