Question

On April 18, 1775, Paul Revere set off on his

midnight ride from Charlestown to Lexington. If he
had ridden straight to Lexington without stopping,
he would have traveled 11 miles in 26 minutes. In
such a ride, what would the average speed of his
horse have been, to the nearest tenth of a mile
per hour?

Answer 1

To find the average speed of Paul Revere's horse, divide the total distance traveled by the total time taken. In this case, the average speed would be approximately 25.41 miles per hour.

Step-by-step explanation:

To find the average speed of Paul Revere's horse, we need to divide the total distance traveled by the total time taken. In this case, the total distance is 11 miles and the total time is 26 minutes.

However, we need to convert the time to hours to match the units of speed. Since there are 60 minutes in an hour, we can convert 26 minutes to hours by dividing it by 60: 26/60 = 0.4333 hours.

Now, we can calculate the average speed by dividing the distance by the time: 11 miles / 0.4333 hours ≈ 25.41 miles per hour.