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2^x=7; evaluate 4^(x-1)

User TheSystem
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1 Answer

5 votes

Answer:


\sf (49)/(4)

Explanation:

Exponent law:


\sf (a^m)/(a^n) =a^(m-n)


\sf 4^(x-1)=(4^x)/(4^1)

Write the expression 4ˣ with base 2.

We know that 4 = 2².


\sf (4^x)/(4)=(2^(2x))/(4)\\\\


\sf= ((2^x)^2)/(4)\\\\\ = (7^2)/(4)\\\\=(49)/(4)

User Milesma
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