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F(x)=x^2+10 what is the average rate of change of f over the interval [-2,1]
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F(x)=x^2+10 what is the average rate of change of f over the interval [-2,1]

User Golan
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1 Answer

5 votes

Answer:

-1

Explanation:


f(-2)=(-2)^2 + 10=14 \\ \\ f(1)=1^2 + 10 =11 \\ \\ (f(1)-f(-2))/(1-(-2))=(11-14)/(3)=-1

User Rupi
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