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What is the point of a horizontal tangent line to the function f(x)=(x^2-5) (x^2+5)​
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4 votes
What is the point of a horizontal tangent line to the function
f(x)=(x^2-5) (x^2+5)​

User CoryT
by
5.3k points

1 Answer

2 votes
Answer: y=-25

When f(x)=(x^2-5)(x^2+5) y equals-25
User Ollpu
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