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What are the solutions for the equation 2x^2+36=0. A) x=+/- 6 B) x=+/- 6i C) x=+/- 3 sqrt 2 D) x= +/- 3i sqrt 2
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What are the solutions for the equation 2x^2+36=0.

A) x=+/- 6
B) x=+/- 6i
C) x=+/- 3 sqrt 2
D) x= +/- 3i sqrt 2

User Lech Birek
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4.0k points

1 Answer

5 votes

Answer:

the answer is x=+/- 3 sqrt 2

User Jcamelis
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4.3k points
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