Question

Can some one help me with this

2s +9
———
3r ÷ s

(If r=-14 and s=6)

Answer 1

25+9

--------

3r÷5

=2×6+9

----------

3×(-14)÷6

=12+9

---------

(-42)÷6

=21

----

-7

=_3

Answer 2

`\huge \boxed{\mathbb{QUESTION} \downarrow}`

2s +9

———

3r ÷ s

(If r = -14 and s = 6)

`\large \boxed{\mathfrak{Answer \: with \:Explanation} \downarrow}`

`\sf(2s + 9)/(3r / s) \\`

Substitute the values of r & s with -14 & 6 respectively.

`\sf\frac { 2 ( 6 ) + 9 } { 3 ( - 14 ) / ( 6 ) } \\`

Multiply 2 and 6 to get 12.

`\sf(12+9)/((3\left(-14\right))/(6)) \\`

Add 12 and 9 to get 21.

`\sf(21)/((3\left(-14\right))/(6)) \\`

Multiply 3 and -14 to get -42.

`\sf(21)/((-42)/(6)) \\`

Divide -42 by 6 to get -7.

`\sf(21)/(-7) \\`

Divide 21 by -7 to get -3.

`= \boxed{ \boxed{\bf \: - 3}}`