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if a^3+b^3=11 and a^3-b^3=5, evaluate a^6-b^6

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Factorize using the difference of squares identity.


a^6 - b^6 = \left(a^3\right)^2 - \left(b^3\right)^2 = \left(a^3 - b^3\right) \left(a^3 + b^3\right)

Then


a^6 - b^6 = 11 \cdot 5 = \boxed{55}

User Ricky Ponting
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