Question

No solution or infinite solutions 5(x+2)-3=3x-8x+7​

Answer 1

x = 0 9Infinite solutions)

Explanation:

Simplifying

5(x + 2) + -3 = 3x + -8x + 7

Reorder the terms:

5(2 + x) + -3 = 3x + -8x + 7

(2 * 5 + x * 5) + -3 = 3x + -8x + 7

(10 + 5x) + -3 = 3x + -8x + 7

Reorder the terms:

10 + -3 + 5x = 3x + -8x + 7

Combine like terms: 10 + -3 = 7

7 + 5x = 3x + -8x + 7

Reorder the terms:

7 + 5x = 7 + 3x + -8x

Combine like terms: 3x + -8x = -5x

7 + 5x = 7 + -5x

Add '-7' to each side of the equation.

7 + -7 + 5x = 7 + -7 + -5x

Combine like terms: 7 + -7 = 0

0 + 5x = 7 + -7 + -5x

5x = 7 + -7 + -5x

Combine like terms: 7 + -7 = 0

5x = 0 + -5x

5x = -5x

Solving

5x = -5x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '5x' to each side of the equation.

5x + 5x = -5x + 5x

Combine like terms: 5x + 5x = 10x

10x = -5x + 5x

Combine like terms: -5x + 5x = 0

10x = 0

Divide each side by '10'.

x = 0.0

Simplifying

x = 0.0

Thanks,

Eddie

Answer 2

`{ \qquad\qquad\huge\underline{{\sf Answer}}}`

Let's solve ~

`\qquad \sf  \dashrightarrow \: 5(x + 2) - 3 = 3x - 8x + 7`

`\qquad \sf  \dashrightarrow \: 5x + 10 - 3 = - 5x + 7`

`\qquad \sf  \dashrightarrow \: 5x + 7 = - 5x + 7`

`\qquad \sf  \dashrightarrow \: 5x = - 5x`

`\qquad \sf  \dashrightarrow \: 5x + 5x = 0`

`\qquad \sf  \dashrightarrow \: 10x = 0`

`\qquad \sf  \dashrightarrow \: x = 0`

Here, we got a unique value of x, that is 0

Therefore, it has an unique solution ~