Question

A locomotive is accelerating at 3.03 m/s2. It passes through a 16.8-m-wide crossing in a time of 3.18 s. After the locomotive leaves the crossing, how much time is required until its speed reaches 32.2 m/s?

Answer 1

Answer: Distance=16.8m

Time=3.18s

Explanation:

Answer 2

First find velocity(initial)

• Distance=16.8m
• Time=3.18s

`\\ \bull\tt\dashrightarrow Velocity=(16.8)/(3.18)`

`\\ \bull\tt\dashrightarrow Velocity=5.2m/s`

• u=5.2m/s
• Final velocity=v=32.2m/s
• Acceleration=a=3.03m/s^2

`\\ \bull\tt\dashrightarrow v=u+at`

`\\ \bull\tt\dashrightarrow t=(v-u)/(a)`

`\\ \bull\tt\dashrightarrow t=(32.2-5.2)/(3.03)`

`\\ \bull\tt\dashrightarrow t=(27)/(3.03)`

`\\ \bull\tt\dashrightarrow t=8.91s`