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Factor completely: x^3−64 A (x−4)3 B (x−4)(x+4)2 C (x−4)(x2+4x+16) D (x+4)(x2−4x+16)
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Factor completely: x^3−64 A (x−4)3 B (x−4)(x+4)2 C (x−4)(x2+4x+16) D (x+4)(x2−4x+16)

User Yaniv Kessler
by
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1 Answer

3 votes

Answer: C

Explanation:

This is the standard difference of cubes factorization.

User Ivan Marinov
by
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