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Jerry has $5 and $10 bills in his wallet. He has a total of 7 bills in his wallet for a total of $50. How many bills does he have of each?

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Final answer:

Jerry has 4 $5 bills and 3 $10 bills in his wallet.

Step-by-step explanation:

To solve this problem, let's assume that Jerry has x number of $5 bills and y number of $10 bills in his wallet.

We are given two pieces of information:

1. Jerry has a total of 7 bills in his wallet, which means x + y = 7.

2. The total value of the bills in his wallet is $50, which means 5x + 10y = 50.

We now have a system of two equations in two variables:

x + y = 7 (Equation 1)

5x + 10y = 50 (Equation 2)

To solve this system, we can use the substitution method or the elimination method. Let's use the elimination method:

Multiply Equation 1 by 5:

5x + 5y = 35 (Equation 3)

Subtract Equation 3 from Equation 2:

5x + 10y - (5x + 5y) = 50 - 35

5y = 15

y = 3

Substitute the value of y back into Equation 1:

x + 3 = 7

x = 4

Therefore, Jerry has 4 $5 bills and 3 $10 bills in his wallet.

User Shane N
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