Question

Who knows how about to do this??

Answer 1

`f(4) = 2`

Explanation:

1.
`f(n)=5n+8`

`f(4)=\\\\f(-2)`

Replace
`n` with
`4`; solve

`f(n)=5n+8\\\\f(n)=5(4)+8\\\\5(4)\\\\20+8\\\\28`

Therefore,
`f(4) = 28`

Replace
`n` with
`-2`

`f(n)=5n+8\\\\f(n)=5(-2)+8\\\\5(-2)\\\\-10+8\\\\-2`

Therefore,
`f(-2) = -2`

2.
`f(n)=-2n+1`

`f(10)=\\\\f(-1)=`

Replace n with 10; solve

`f(n)=-2n+1\\\\f(n)=-2(10)+1\\\\-2(10)\\\\-20+1\\\\-19`