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What is the solution to the trigonometric inequality 2-3csc(x) > 8 over the interval radians?

User DrowZ
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2 Answers

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2 - 3csc(x) > 8 \\ 2 - (3)/(sin(x)) > 8 \\ - 6 > (3)/(sin(x)) \\ - 2 > (1)/(sin(x)) \\ ( - 1)/(2) < sin(x) \: \: or \: \: \: sin(x) > ( - 1)/(2) \\ \\


sin( ( - \pi)/(6) ) = ( - 1)/(2)


x \: in \: \: [0, (7\pi)/(6)[U] (11 \pi )/(6) ,2\pi] + 2k\pi

User Dec Sander
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4 votes

Answer:

D. pi<x<7pi/6 and 11pi/6<x<2

Explanation:

Took the test and this is the correct answer

What is the solution to the trigonometric inequality 2-3csc(x) > 8 over the interval-example-1
User Globalfish
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