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12-3p^2....difference of two squares

User Reunanen
by
8.3k points

2 Answers

3 votes

Answer:

(2√3)² − (p√3)²

Explanation:

12 − 3p²

= 4×3 − 3p²

= 2²×(√3)² − (√3)²×p²

= 2²×(√3)² − p²×(√3)²

= (2√3)² − (p√3)²

Conclusion :

12 − 3p² Written as a difference of two squares :

(2√3)² − (p√3)²

User MonteCristo
by
7.7k points
7 votes

Answer:

= 3(2 - p)(2 + p)

Explanation:

12 - 3p² =

First factor out a common factor, 3.

= 3(4 - p²)

Now factor the difference of 2 squares.

= 3(2 - p)(2 + p)

User Yehnan
by
8.9k points

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