Question

Write the equation of the line perpendicular to 2x-5y=-12 that passes through the point (10,-1)

Answer 1

y = - 5/2x + 24

Explanation:

2x - 5y = - 12. (10, -1)

- 5y = - 2x - 12

y = -2/-5x -12/-5

y = 2/5x + 12/5

Slope: 2/5 (slope of the perpendicular line: - 5/2)

y - - 1) = - 5/2(x - 10)

y + 1 = - 5/2x + 25

y = - 5/2x + 24