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Point P' is the image of P(6, 0) under the translation (x, y) → (x-6, y - 1). What are the coordinates of P'?
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Point P' is the image of P(6, 0) under the translation (x, y) → (x-6, y - 1).

What are the coordinates of P'?

User JamesTBennett
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8.3k points

1 Answer

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Answer:

P' = (6-6,0-1)

P' = (0,-1)

User Akshay Mulgavkar
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