Answer:
x=2 and x=-2
Explanation:
Original Equation:

Add 6x to both sides

Subtract 4 from both sides

Use difference of squares:


Since the factors are being multiplied by each other, if one of the factors is equal to zero, then the entire thing becomes zero, since 0 * anything = 0
So to find the values of x that satisfy this equation, set each factor equal to zero

Add 2 to both sides


subtract 2 from both sides

We have both values that satisfy this equation, x=2 and x=-2