Final answer:
The heat energy absorbed by 125 g of water is approximately 3295.5 J.
Step-by-step explanation:
The specific heat of water is 4.184 J/g °C. To calculate the heat energy absorbed by the water, we can use the formula:
q = mcΔT
where q is the heat energy, m is the mass of the water, c is the specific heat of water, and ΔT is the change in temperature.
Given that m = 125 g, c = 4.184 J/g °C, and ΔT = 30 °C - 22.5 °C = 7.5 °C, we can plug in these values:
q = (125 g)(4.184 J/g °C)(7.5 °C) = 3295.5 J
Therefore, the heat energy absorbed by 125 g of water is approximately 3295.5 J.