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Two friends are planning for a gathering. The food budget is modeled by one half times the absolute value of the quantity x minus 120 end quantity equals 10 comma where x is the amount spent on food. What are the least and greatest amounts that the two friends could spend on food?

$50, $70
$100, $140
$110, $130
$115, $125

2 Answers

4 votes

Answer:

100, 140

Step-by-step explanation:

User Azeame
by
8.1k points
4 votes

Answer:

$100, $140

Step-by-step explanation:


\sf \rightarrow (1)/(2) |x-120| = 10


\sf \rightarrow |x-120| = 2(10)


\sf \rightarrow |x-120| = 20


\sf \rightarrow x-120 = \pm 20


\sf \rightarrow x-120 = 20 \quad or \quad x - 120 = -20


\sf \rightarrow x= 20+120 \quad or \quad x = -20+120


\sf \rightarrow x= 140\quad or \quad x = 100

Hence, the least amount is $100 and greatest amount is $140.

User MJSG
by
7.0k points

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