Question

Consider this equation. cos(θ)= -3/10 If θis an angle in quadrant II, what is the value of tan (θ)?

PLEASE HELP DUE IN 2 HOURS

Answer 1

C)

Explanation:

Trigonometry ratio:

`\sf Cos \ \theta = (Adjacent \ side)/(hypotenuse)=(-3)/(10)`

We need to find the opposite side using Pythagorean theorem.

opposite side² = hypotenuse² - adjacent side²

= 10² - (-3)²

= 100 - 9

= 91

opposite side = √91

`\sf tan \ \theta = (opposite \ side)/(adjacent \ side)`

`\sf = (√(91))/(3)`

In quadrant II, value of tan
`\theta` is negative.

`\sf tan \ \theta = -(√(91))/(3)`