Final answer:
The car initially moving at 5 m/s and accelerating to 17 m/s over 2 seconds traveled a distance of 22 meters.
Step-by-step explanation:
Considering the car's initial velocity (Vo) of 5 m/s, final velocity (Vf) of 17 m/s over a time (t) of 2 seconds, we can calculate the acceleration (a) using Equation 1: Vf = Vo + at. Rearranging the equation to solve for acceleration gives us a = (Vf - Vo) / t.
Using these values, we find a = (17 m/s - 5 m/s) / 2 s = 6 m/s2. Now, with acceleration and time, we can apply Equation 3: Xf = Xo + vot + 1/2at2, which calculates the displacement (x).
Assuming an initial position (Xo) of 0, the equation simplifies to x = Vo*t + 1/2*a*t2. Therefore, the distance traveled by the car is x = 5 m/s * 2 s + 1/2 * 6 m/s2 * (2 s)2 = 10 m + 12 m = 22 meters.