Answer: the cost of each balloon is $1, the cost of each banner is $2.
Explanation:
Let the cost of each balloon is x, and the cost of each banner is y.
Hence,
![\displaystyle\\\left \{ {{3x+2y=7\ \ \ \ (1)} \atop {6x+3y=12\ \ \ \ (2)}} \right. \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/jkbp9rzyimnwoyssvowfxvww2aljowkk6a.png)
We multiply equation (1) by -2:
![\displaystyle\\\left \{ {{-6x-4y=-14} \atop {6x+3y=12}} \right. \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/2vhljrthkt63gxibhbkfa6ffkx4qsruo2a.png)
Let's sum up these equations:
![-y=-2\\](https://img.qammunity.org/2023/formulas/mathematics/high-school/hx6z0h7rook8xgjfjpuazahhwdbc55qxho.png)
Multiply both sides of the equation by -1:
![y=2.\\](https://img.qammunity.org/2023/formulas/mathematics/high-school/isyzwexa6qos0hzawmne0fjuk070jt1m24.png)
We substitute the value of y into equation (1):
![3x+2*2=7\\3x+4=7\\3x+4-4=7-4\\3x=3\\](https://img.qammunity.org/2023/formulas/mathematics/high-school/46lzjwhtzbsdepgagx9iam7uqww34jwr7p.png)
Divide both sides of the equation by 3:
![x=1.](https://img.qammunity.org/2023/formulas/mathematics/high-school/mc3y77p8ezqfd9nuc6fl6n02bw352dn9yv.png)