Question

A nuclear fission reaction has mass difference between the products and the reactants of 0.0284 amu. Calculate the

amount of energy released by the reaction.
A)
1.41 x 10-20
B)
1.57 x 10-37
C)
4.24 x 10-12
D)
5.24 x 10-46)

Answer 1

C) 4.24 x
`10^(-12)`

Step-by-step explanation:

E = Δm
`c^(2)`

Δm = 0.0284 x 1.66 x
`10^(-27)` kg = 4.714x
`10^(-29)`kg

putting value in above equation

E = 4.714x
`10^(-29)`kg x (3x
`10^(8)`
`)^(2)` = 4.24 x
`10^(-12)`