Answer:
C(h,w)=5w²+8(h*w)
Step-by-step explanation:
Let w be the name of the width of this storage.
Let h be the height of the storage.
Constraint: w²h=8 cubic meters.
Taking into acount that the base of this storage is a square, width=length.
Area of the base: w²
•The cost of the base is given by:
C(b)=$5*w²=
5w²
•The cost of the sides is given by:
C(s)={$2*(h*w)}*4
We multiply by 4 because there are 4 sides.
C(s)=8(h*w)
•The total cost should be given by:
C(h,w)=5w²+8(h*w)
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To verify this answer let's illustrate an example and solve it.
Let's say we have a storage with a base of 9m² (3 by 3, each side=3) and then the height of the storage is 4m.
Let's plug the values into the formula and try to find the total cost:
C(4,3)=5(3)²+8(4*3)= $141.
Area of the base was 9, 9*5= $45.
Area of the 4 sides should be 4*3*4= 48, 48*2= $96
$45+$96= $141, that's correct!