Question

Please

Help

Please help. See the picture

Answer 1

• General equation of a line is as below:

`{ \boxed{ \tt{y = mx + c}}} \\`

→ m is the slope

`{ \tt{slope = (y _(2) - y _(1) )/(x _(2) - x _(1) ) }} \\`

• Consider points (0, 3) and (3, 0) from the graph:

`{ \tt{slope = (0 - 3)/(3 - 0) = ( - 3)/(3) }} \\ \\ { \tt{ \underline{ \: \: slope = - 1 \: \: }}}`

→ c is the y-intercept:

• consider point (0, 3):

`{ \tt{y = mx + c}} \\ { \tt{3 = ( - 1 * 0) + c}} \\ { \tt{c = 3}}`

» Therefore, substitute to make the equation of a line:

`{ \boxed{ \boxed{ \tt{ \: \: y = - x + 3 \: \: }}}}`