Answer:
y=1 , z=-2
Explanation:
I will use the method of elimination :
Multiply the top equation by 5 to make equation 3 :
35z + 15y = -55
Multiply bottom equation by 3 to make equation 4:
6z + 15y = 3
Subtract equation 3 from equation 4 to eliminate the y :
-29z = 58
Divide both sides by -29 to solve for z :
z = 58 ÷ -29
z = -2
Substitute this value into either equation 1 or 2 to solve for y :
I chose equation 2 :
2(-2) + 5y = 1
-4 + 5y = 1
Add 4 to both sides :
5y = 5
Divide both sides by 5 :
y = 1
Hope this helped and have a good day