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What is the solution to the system of equations?
7z+3y=-11
2z+ 5y = 1

1 Answer

2 votes

Answer:

y=1 , z=-2

Explanation:

I will use the method of elimination :

Multiply the top equation by 5 to make equation 3 :

35z + 15y = -55

Multiply bottom equation by 3 to make equation 4:

6z + 15y = 3

Subtract equation 3 from equation 4 to eliminate the y :

-29z = 58

Divide both sides by -29 to solve for z :

z = 58 ÷ -29

z = -2

Substitute this value into either equation 1 or 2 to solve for y :

I chose equation 2 :

2(-2) + 5y = 1

-4 + 5y = 1

Add 4 to both sides :

5y = 5

Divide both sides by 5 :

y = 1

Hope this helped and have a good day

User Scott Montgomerie
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