Question

Factorise and divide: (3y^8 - 4y^6 + 5y^4) ÷ y^3

Answer 1

`\star→ \: { \sf{ \frac{ \{ {3y}^(8) - {4y}^(6) + {5y}^(4) \}}{ {y}^(3) } }} \\`

• factorization:

`\star→ \: { \sf{ \frac{ {y}^(3)(3y {}^(5) - 4 {y}^(3) + 5 {y} }{ {y}^(3) }}} \\ \\ \star→ \: { \sf{ \frac{ {y}^(3) }{ {y}^(3) } .^{}(3y {}^(5) - 4 {y}^(3) + 5 {y}}})`

• divide:

`= { \boxed{ \boxed{ \sf{y(3 {y}^(4) - 4 {y}^(2) + 5)}}}}`