Question

The sum of an integer and 8 times the next

consecutive odd integer is 43. Find the
value of the greater integer.

Answer 1

5

Explanation:

Let x = the first integer (smaller)

Let x +2 = the next odd integer

x + 8(x +2) = 43 Distribute the 8

x + 8x + 16 = 43 Add the x's

9x + 16 = 43 Subtract 16 from both sides

9x = 27 Divide both sides by 9

x = 3

This is your first number. The next consecutive odd integer would be 5. (x + 2)