Answer:
x-2y+18=0 is required eqn
Explanation:
Let, (-4,7) be X1,Y1
(-6,2) be X2,Y2
Now,
Eqn of st.line is (y-y1)=m (x-x1).....[m= y2-y1/x2-x1 ]
(y-7) = 2-7/(-6-4) * (x+4)
(y-7) = -5/-10 * (x+4)
(y-7) = 1/2 * (x+4)
2y-14 = x+4
x-2y+18=0 is req eqn
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