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Physics question about work

Physics question about work-example-1

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W = Fdcosθ
W = (222N)(0.60m)cos120°
W = -66J

For the second part, use of a kinematics equation is useful.

Known values:

Initial velocity = 11m/s
Final velocity = 0m/s
Acceleration = 222/6m/s^2 (since F = ma, therefore a = F/m)

Kinematics equation: Vf^2 = Vi^2 + 2aΔd

Rearrange to solve for Δd.

(Vf^2 - Vi^2)/2a = Δd

Plug in values.

(-(11)^2)/2((222\6)) = -1.6m
User Cristian Necula
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