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If the image of a and 3 under the function f (x) = x+ 3b are 5 and 6 respectively, fing the value of a and b​

User Hashier
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f(3)=3+3b=6 \implies \boxed{b=1} \\ \\ f(a) = a+3b = 5 \implies \boxed{a=1}

User Frederika
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