Question

Please help with question below

Answer 1

Hypotenuse = 15

Adjacent =x

H + A = cah or cos

Cos(53) = x/15

x15

15 x Cos(53) = x

x = 9.0272...

Ans: A) 9.0m

Hope this helps!

Answer 2

○ a)
`\displaystyle 9\:m.`

Explanation:

`\displaystyle (15)/(x) = sec\:53 \hookrightarrow xsec\:53 = 15 \hookrightarrow (15)/(sec\:53) = x \hookrightarrow 9,0272253473... = x \\ \\ 9 ≈ x`

OR

`\displaystyle (x)/(15) = cos\:53 \hookrightarrow 15cos\:53 = x \hookrightarrow 9,0272253473... = x \\ \\ 9 ≈ x`

Information on trigonometric ratios

`\displaystyle (OPPOCITE)/(HYPOTENUSE) = sin\:θ \\ (ADJACENT)/(HYPOTENUSE) = cos\:θ \\ (OPPOCITE)/(ADJACENT) = tan\:θ \\ (HYPOTENUSE)/(ADJACENT) = sec\:θ \\ (HYPOTENUSE)/(OPPOCITE) = csc\:θ \\ (ADJACENT)/(OPPOCITE) = cot\:θ`

I am joyous to assist you at any time.