Answer:
1st balance the reaction
3AgNo3 + AlCl3 = Al(No3)3+ 3AgCl.
Assuming 100% reaction yield.
1 mole of AlCl3 will produce 3 moles os AgCl.
hence, when 3 moles of AlCl3 reacts, then the tlreaction will produce (3×3) = 9 moles of AgCl.
ans= 9 moles.