Question

If 21.9 grams of an aqueous solution of zinc sulfate, ln(S*O_{4}) , contains 4.44 grams of zinc sulfate, what is the percentage by mass of zinc sulfate in the solution?

Answer 1

20.27%.

Step-by-step explanation:

Divide the mass of zinc sulfate (4.44g) by the total mass of the solution (21.9) and multiply for 100 to get the percentage:

`(4.44g)/(21.9g)*100= 20.27`%.