At time
(in hours), train W travels a distance of
![(45\,\mathrm{mph})t](https://img.qammunity.org/2023/formulas/mathematics/high-school/n7tuec7r1vdqns80fogg26867oq75tpumw.png)
away from Abbington. Meanwhile, train X starts 150 mi away from Abbington and is getting closer, so its distance from Abbington is
![150\,\mathrm{mi} - (55\,\mathrm{mph})t](https://img.qammunity.org/2023/formulas/mathematics/high-school/yeqytjlsiq4rjlu8sk3eqvdj8e91fuy5ga.png)
When the two trains meet, we have
![45t = 150 - 55t](https://img.qammunity.org/2023/formulas/mathematics/high-school/92uhs7nr93xzytyp2shc0hh7sbumwtbriv.png)
Solve for
.
![45t = 150 - 55t \implies 100t = 150 \implies t = (150)/(100) = 1.5](https://img.qammunity.org/2023/formulas/mathematics/high-school/k4ufs6upzysps6uyf3oakzk0szqb20tjw1.png)
The trains pass each other after 1.5 hours, at which point train W will have traveled a distance of
![(45\,\mathrm{mph})(1.5\,\mathrm h) = \boxed{67.5\,\rm mi}](https://img.qammunity.org/2023/formulas/mathematics/high-school/lklnm4w7o04j3spfzc64j5iynterw9a8xt.png)