Question

If Given three resistors 10 ohm, 15 ohm and 1 ohm.

Supply voltage is Vs= 25 V. (a) If the resistors are connected in

series across Vs, find the volt drop across each resistor. (b) If the

resistors are connected in parallel across Vs, find the currents in

each resistor. (c) In both cases if the 1 ohm resistor becomes

burnt, explain what happens to the circuits?​

Answer 1

See below

Step-by-step explanation:

A In series the resistances are additive = 26 ohms

the current is then V = IR

V/R = I 25 / 26 = .962 A

V = IR again for each resistor

10 ohm: 10 * .962 = 9.62 v

15 ohm: 15 * .962 = 14.4 v

1 ohm: 1 * .962 = . 962 v

B In parallel, the EACH have 25 v applied

V = IR I = V/R

10 ohm 25 v / 10Ω = 2.5 A

15 Ω 25 v / 15Ω = 1.67 A

C In series, if ANY Of the resistors burn out (open circuit).....no current will flow through the circuit.....

In parallel, if one burns out, the other two will have the same current as before the burnout