202k views
1 vote
How do you factor 4m^3+12xm^3-8m^2-24m using GCF

User Liviucmg
by
8.1k points

1 Answer

0 votes

Answer:


4m(m {}^(2) + 3xm {}^(2) - 2m - 6)

Explanation:


1. \: gcf = 4m \\ 2. \: 4m( \frac{4m {}^(3) }{4m} + \frac{12xm {}^(3) }{4m} + \frac{ - 8m {}^(2) }{4m} + ( - 24m)/(4m) ) \\ 3. \: 4m(m {}^(2) + 3xm {}^(2) - 2m - 6)

User Zamber
by
7.6k points

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