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The maximum value of 12 sin 0-9 sin²0 is: -​

User Afiya
by
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1 Answer

5 votes

Answer:

4

Explanation:

The question is not clear. You have indicated the original function as 12sin(0) - 9sin²(0)

If so, the solution is trivial. At 0, sin(0) is 0 so the solution is 0

However, I will assume you meant the angle to be
\theta rather than 0 which makes sense and proceed accordingly

We can find the maximum or minimum of any function by finding the first derivate and setting it equal to 0

The original function is


f(\theta) = 12sin(\theta) - 9 sin^2(\theta)

Taking the first derivative of this with respect to
\theta and setting it equal to 0 lets us solve for the maximum (or minimum) value

The first derivative of
f(\theta) w.r.t
\theta is


12\cos\left(\theta\right)-18\cos\left(\theta\right)\sin\left(\theta\right)

And setting this = 0 gives


12\cos\left(\theta\right)-18\cos\left(\theta\right)\sin\left(\theta\right) = 0

Eliminating
cos(\theta) on both sides and solving for
sin(\theta) gives us


sin(\theta) = (12)/(18) = (2)/(3)

Plugging this value of
sin(\theta) into the original equation gives us


12((2)/(3)) - 9((4)/(9) ) = 8 - 4 = 4

This is the maximum value that the function can acquire. The attached graph shows this as correct

The maximum value of 12 sin 0-9 sin²0 is: -​-example-1
User ExilonX
by
8.1k points

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