Answer:
![l = \boxed{167.}\\w=\boxed{40.}](https://img.qammunity.org/2023/formulas/mathematics/college/qss5yayd6xm11bat8r6yxixrtd1do33j24.png)
Explanation:
Since the perimeter is 414 meters, half of the perimeter is 207 meters. We can write the following equation and solve for h.
![w + l = 207\\w + (4w + 7) = 207\\5w +7 = 207\\5w = 200\\w = \boxed{40.}](https://img.qammunity.org/2023/formulas/mathematics/college/kw0a6l2w0fy6ii0lq6xfqsx95v36qsxjp6.png)
Here, we substituted 4w + 7 in place of l as the problem tells us that the length of the pool is 7 meters more than 4 times the width. Solving for the width gave us 40 meters.
Using this information, we can determine that the length of the swimming pool is:
![4(40) + 7 = 160 + 7 = 167.](https://img.qammunity.org/2023/formulas/mathematics/college/g2xxxcjoo2yjv77mtuc9pun3low1h4riwq.png)
To double-check that this is correct, we can add twice the length and twice the width to see if it equals the given perimeter:
![167 + 167 + 40 + 40 = 414.](https://img.qammunity.org/2023/formulas/mathematics/college/2jpezgj9vj8o3xd2w5w9qbroycekxz07jp.png)
Therefore, your length and width of this swimming pool are:
![l = \boxed{167.}\\w=\boxed{40.}](https://img.qammunity.org/2023/formulas/mathematics/college/qss5yayd6xm11bat8r6yxixrtd1do33j24.png)